If this condition is not met, then the value in B1 is returned. Note that the words "under ten" are returned if the value in A1 is less than 10. For instance, let's say that your formula is in cell B1 and you are comparing something in cell A1. The obvious solution, then, is to make sure that you provide the IF function with something that should be returned when the comparison is false. (This is what Vineet is seeing returned by his IF function usage.) It is possible to leave off the last parameter, but if you do then Excel will return the value 0 if the comparison is false. The first parameter is the comparison that is to be made, the second parameter is what should be returned if the comparison is true, and the third is what should be returned if the comparison is false.
The IF function can take up to three parameters. By default, however, the IF function makes the value 0 if the condition is False. In other words, the value in a cell where the IF function is used should change only if the condition being tested by the IF function is true. If the value is between 250,001 and 250,001, it would calculate 0% on the first 125,000, 2% on the next 125,000 and 5% on the remainder.While using the IF function, Vineet wants to retain the old value in the cell if the condition is false. If the value is between 125,001 and 250,000, it would calculate 0% on the first 125,000 and 2% on the remainder. If the value was below 125,000, the formula would return 0. The first 125,000 attracts 0%, the next 125,000 to 250,000 attracts 2%, and so on.Īnswer:This adds a level of complexity to our formula since we have to calculate each range of the number using a different percentage. This is why we can simplify the formulas within the nested IF functions, instead of testing ranges using two comparisons such as AND(B1>=125001, B11500000 =12% Excel will evaluate each condition and stop when a condition is TRUE. Since your IF conditions will cover all numbers in the range of 0 to >1500000, it is easiest to work backwards starting with the >1500000 condition. We will assume that your number 'n' resides in cell B1. Can you help?Īnswer:You can create this formula using nested IF functions. I realise it's probably an 'IF(AND)' function but I appear to require too many arguments.
If A2 = 63, the formula will return 1 (third IF function) If A2 = 80, the formula will return 2 (second IF function) If A2 >= 95, the formula will return 3 (first IF function) Question:I have read your piece on nested IFs in Excel, but I still cannot work out what is wrong with my formula please could you help? Here is what I have: =IF(6395,3,0)))Īnswer: The simplest way to write your nested IF statement based on the logic you describe above is: =IF(A2>=95,3,IF(A2>=80,2,IF(A2>=63,1,0))) Can you help me with the IF function on this one?Īnswer: You can write a nested IF statement that uses the AND function and the ISBLANK function as follows: =IF(AND(ISBLANK(A2)=FALSE,A2>=0),C1+A2, IF(AND(ISBLANK(B2)=FALSE,B2>=0),C1-B2, IF(AND(ISBLANK(A2)=TRUE, ISBLANK(B2)=TRUE),C1,""))) If both A2 and B2 are blank then equals C1. If cell B2 is greater than or equal to 0 then subtract from C1.
If cell A2 is greater than or equal to 0 then add to C1. For example: =IF(A1 4 but 9 but 15, return $75Īnswer:In cell C5, you can write a nested IF statement that uses the AND function as follows: =IF((A1+B1)4,(A1+B1)9,(A1+B1)1,000,000 then A1*.01% but maximum 5000Īnswer: You can write a nested IF statement that uses the MAX function and the MIN function as follows: =IF(A11000000,MIN(5000,A1*0.01%),"")) If its is greater than or equal to 50 and less than 100, then multiply by 3Īnd if it is great or equal to than 100, then multiply by 4Īnswer: You can write a nested IF statement to handle this.
If it is greater than or equal to 20 but less than 50, then multiply by 2 If (cell A1) is less than 20, then multiply by 1, Question: In Microsoft Excel, I need to write a formula that works this way:
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